Suppose vector a = 2i + 4j - 5k; vector b = λi + 2j + 3k
Then vector(a + b) = (2 + λ)i + 6j - 2k
Along the unit Vector, sum of these vectors

= 1 x (2 + λ) + 1 x 6 + 1 x (-2) = √((2 + λ)2 + 40)
λ + 6 = √((2 + λ)2 + 40)
λ2 + 12λ + 36 = 4 + 4λ + λ2 + 40
12λ + 36 = 4λ + 44
λ = 1