Question

If c > 0 and 4a + c < 2b, then ax² - bx + c = 0 has a root in the interval

(A)  (0, 2)

(B)  (2, 4) 

(C)  (0, 1)

(D)  (−2, 0)

Answer 1

Correct option (A) (0, 2)

 

f(x) = ax² - bx + c = 0

f(0)  = c > 0

f(2) = 4a - 2a + c < 0

So, the equation has a root which lies in the range (0, 2).