Question

The number of real solutions of the equation |x|² - 4|x|+3 = 0 is

(A)  4

(B)  2 

(C)  1

(D)  3

Answer 1

Correct option  (A) 4

|x|² - 4|x| + 3 = 0

⇒ (x|-3|)(|x|-1) = 0

⇒ |x| = 1 or |x| = 3

⇒ x = ±1 or x = ± 3a

So, the number of solutions is 4.