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1 Answer

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The given differential equation is 

p2y + 2px = y ...(i)

2px = y – p2y

x = (y – p2y)/2p

Differentiating, w.r.t. y, we get

py = c ...(ii)

Eliminating p between Eqs (i) and (ii), we get 

y2 + 2cx = c2

which is the required solution.

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