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Solve √(x + 3 - 4)√(x - 1) + √(x + 8 - 6)√(x - 1) = 1 for x.

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Solve √(x + 3 - 4)√(x - 1) + √(x + 8 - 6)√(x - 1) = 1 for x.

(A)  {5,10}

(B)  [1, ∞)

(C)  [5,10]

(D)  None of these

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Correct option  (C) [5 ,10] 

Putting x − 1 = t2 in the given equation, we get

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