Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE

1 Answer

0 votes
by (33.2k points)
selected by
 
Best answer

The given differential equation is 

(d2y/dx2) = x + sin x

(d/dx)(dy/dx) = x + sin x

Integrating, we get

dy/dx = (x2/2) - cos x + c1

Again integrating, we get 

y = (x3/6) – sin x + c1x + c2

which is the required solution

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...