(a) Formation of delegation means selection of 4 out of 12. Hence, the number of ways = 12C4 = 495.
(b) Two particular students are already selected. Here we need to select only 2 out of the remaining 10. Hence, the number of ways = 10C2 = 45.
(c) The number of ways in which both are selected = 45. Hence, the number of ways in which the two are not included together
= 495 – 45 = 450.
(d) There are two possible cases:
(i) Either both are selected. In this case, the number of ways in which the selection can be made = 45.
(ii) Or both are not selected. In this case, all the four students are selected from the remaining 10 students.
This can be done in 10C4 = 210 ways.
Hence, the total number of ways of selection is
45 + 210 = 255
(e) We assume that students A and B wish to be selected together and students C and D do not wish to be together.
Now there are following 6 cases:
(i) (A, B, C) selected, (D) not selected
(ii) (A, B, D) selected, (C) not selected
(iii) (A, B) selected, (C, D) not selected
(iv) (C) selected, (A, B, D) not selected
(v) (D) selected, (A, B, C) not selected
(vi) A, B, C, D not selected
For (i), the number of ways of selection = 8C1 = 8
For (ii), the number of ways of selection = 8C1 = 8
For (iii), the number of ways of selection = 8C2 = 28
For (iv), the number of ways of selection = 8C3 = 56
For (v), the number of ways of selection = 8C3 = 56
For (vi), the number of ways of selection = 8C4 = 70
Hence, total number of ways = 8 + 8 + 28 + 56 + 56 + 70 = 226