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The solution of x^2(dy/dx) - xy = 1 + cos(y/x) is (A) tan(y/2x)= c - 1/2x^2

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The solution of x2(dy/dx) - xy = 1 + cos(y/x) is

(A) tan(y/2x)= c - 1/2x2

(B) tan(y/x) = c + 1/x

(C) cos(y/x) = 1 + c/x

(D) x2 = (c + x2)tan(y/x)

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Answer is (A) tan(y/2x)= c - 1/2x2

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