Question

The area (in sq. units) of the parallelogram, whose diagonals are along the vectors 8i - 6j and 3i + 4j - 12k, is

(A) 65 

(B) 52 

(C) 26 

(D) 20 

Answer 1

Answer is (A) 65

The area of parallelogram when diagonals are given is

The given vectors are d₁ = 8i - 6j and d₂ = 3i + 4j - 12k.

Therefore, from Eq. (1), we get

Therefore, the area of the parallelogram is