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If 1/(p + q),1/(r + p),1/(q + r) are in Ap,then

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in Binomial theorem by (46.7k points)

If 1/(p + q),1/(r + p),1/(q + r) are in Ap,then

(A)  p,q,r are in AP

(B)  p2,q2,r2 are in AP

(C)  1/p,1/q,1/r  are in AP

(D) None of these

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1 Answer

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Best answer

Correct option (B)  p2,q2,r2 are in AP

Therefore,p2,q2,r2 are in AP.

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