Question

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination (s) has/have the same energy lists.

1. n = 4, l = 2, m₁ = -2, m_s = -1/2

2. n = 2, l = 2, m₁ = 1, m_s = +1/2

3. n = 4, l = 1, m₁ = 0, m_s = +1/2

4. n = 3, l = 2, m₁ = -2, m_s = -1/2

5. n = 3, l = 1, m₁ = -1, m_s = +1/2

6. n = 4, l = 1, m₁ = 0, m_s = +1/2

Answer 1

(i) Represents 4d orbital (ii) Represents 3d orbital, (iii) Represents 4p orbital (iv) Represents 3d orbital (v) Represents 3p orbital (vi) represents 4p orbital

3p < 3d < 4p < 4d

Combination (2) n = 3, l = 2, m₁ = 1, m_s = +1/2 and combination (4) n = 3, l = 2, m₁ = -2 and m_s = -1/2 have the same energy lists.

Similarly combination (3) n = 4, l = 1, m₁ = 0, and m_s = 1/2 and combination (6) n = 4, l = 1, m₁ = 0, m_s = +1/2 have the same energy lists.

Therefore, (v) < (iii) = (iv) < (vi) = (iii) < (i)