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If the sum of the coefficients of all even powers of x in the product (1 + x + x2 + ... + x2n) (1 - x + x2 - x3 + ... + x2n) is 61, then n is equal to _________.

2 Answers

+1 vote
by (52.8k points)
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Best answer

Let (1 + x + x2 +…+ x2n) (1 - x + x2 - x3 +…+x2n

= a0 + a1x + a2x2 + a3x3 + a4x4 +…+a4nx4n

So, a0 + a1 + a2 +…+ a4n = 2n + 1 …(1)

a0 - a1 + a2 - a3…+ a4n = 2n + 1 …(2)

⇒ a0 + a2 + a4 +…+a4n = 2n + 1

⇒ 2n + 1 = 61 ⇒ n = 30

+1 vote
by (58.5k points)

Let (1 - x + x2 .....) (1 + x + x2 ......)

= a0 + a1 x + a2x2 + .........

Put x = 1

1(2n + 1) = a0 + a1 + a2 + ......a2n .....(i)

put x = -1

(2n + 1) × 1 = a0 - a1 + a2 +........a2n ........(ii)

Form (i) and (ii)

4n + 2 = 2(a0 + a2 +....)

= 2 × 61

⇒ 2n + 1 = 61 ⇒ n = 30

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