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Calculate the solubility of Ag2CrO4 4 in 0.1 M AgNO3Ksp of Ag2 CrO4 = 1 × 10^-12

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Calculate the solubility of Ag2CrO4 4 in 0.1 M AgNO3Ksp of Ag2 CrO4 = 1 × 10-12

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Ksp = [Ag+]2 [CrO42-] 

1 × 10-12 = (2 x 0.1)2 [CrO42-]

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