Question

For the following reactions :

k_s and k_e, are, respectively, the rate constants for the substitution and elimination, and μ = k_s/k_e, the correct options is -

(1) μ_B > μ_A and k_e(B) > k_e(A)

(2) μ_B > μ_A and k_e(A) > k_e(B)

(3) μ_A > μ_B and k_e(B) > k_e(A)

(4) μ_A > μ_B and k_e(A) > k_e(B)

Answer 1

Answer is (1) μ_B > μ_A and k_e(B) > k_e(A)

(B) with more steric crowding forms elimination product compared to substitution.

Answer 2

Answer is (1) μ_B > μ_A and k_e(B) > k_e(A)

Substitution will be fast when

and elimination will be fast when