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The reaction of H3N3B3Cl3 (A) with LiBH4 in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to H3N3B3(Me)3. Compounds (B) and (C) respectively, are: 

(1) Boron nitride and MeBr 

(2) Borazine and MeMgBr 

(3) Borazine and MeBr 

(4) Diborane and MeMgBr

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