The reaction of H3N3B3Cl3 (A) with LiBH4 in tetrahydrofuran gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to H3N3B3(Me)3. Compounds (B) and (C) respectively, are:
(1) Boron nitride and MeBr
(2) Borazine and MeMgBr
(3) Borazine and MeBr
(4) Diborane and MeMgBr