Question

A chemist has 4 samples of artificial sweetener A, B, C and D. To identify these samples, he performed certain experiments and noted the following observations : 

(i) A and D both form blue-violet colour with ninhydrin. 

(ii) Lassaigne extract of C gives positive AgNO₃ test and negative Fe₄[Fe(CN)₆]₃ test. 

(iii) Lassaigne extract of B and D gives positive sodium nitroprusside test 

Based on these observations which option is correct ?

(1) A : Aspartame; B: Saccharin;

C: Sucralose; D; Alitame

(2) A: Alitame; B: Saccharin;

C: Aspartame; D; Sucralose

(3) A: Saccharin; B: Alitame;

C: Sucralose; D; Aspartame

(4) A: Aspartame; B: Alitame;

C: Sacchrin; D; Sucralose

Answer 1

Answer is (1)

(i) Blue voilet color with Ninhydrine → amino acid derivative. So it cannot be saccharide or sucralose.

(ii) Lassaigne extract give +ve test with AgNO₃. So Cl is present, –ve test with Fe₄[Fe(CN)₆]₃ means N is absent. So it can't be Aspartame or Saccharine or Alitame, so C is sucralose.

(iii) Lassaigne solution of B and D given +ve sodium nitroprusside test, so it is having S, so it is Saccharine and Alitame.

Answer 2

Answer is (1)

(C) is sucralose because it gives positive test with AgNO₃ 

(B) is Saccharin because it gives positive test with sodium nitro prusside. 

Aspartame and alitame both give blue violet colour with ninhydrin.