Question

If in case df a motion, displacement is directly proportional to the square of the tune elapsed, what do you think about its acceleration, le, constant or variable? Explain why?

Answer 1

x ∝ t²

⇒ x = kt²

Where k is a constant

a = ((d/dt)(dx/dt)) = (2 k t)

= 2 k = constant

∴ Acceleration is constant.