Lat = |(1,1,1),(a,b,c),(bc,ca,ab)|
= |(1,0,0),(a,b - a,c - b),(bc,ca - bc,ab - ca)|
[By C2 → C2 - C1 and C3 → C3 - C2]
= |(1,0,0),(a,-(a - b),-(b - c),(bc,c(a - b),a(b - c)|
= (a - b)(b - c)|(1,0,0),(a,-1,-1),(bc,c,a)|
[Taking common (a - b) from C2 & (b - c) from C3
= (a - b)(b - c).1(-a + c)
= (a - b)(b - c)(c - a)