Given Sn = pn + qn2 ………………(1)
Substituting n = 1, 2, we get
S1 = p(1) + q(1)2 = p + q and
S2 =p(2) + q(2)2 =2p + 4q
we know that, S1 = a = first term and S2 = first term + second term = a + (a + d),
where d = C.D.
S2 = 2a + d = 2p + 4q = 2 (p + q) + d = 2p + 2q + d
= d = 2p + 4q - 2p - 2q = 2q