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If the sum of ‘n’ terms of an A.P.is (pn + qn2), where p and q are constant find the common difference.

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Given S= pn + qn2  ………………(1) 

Substituting n = 1, 2, we get 

S1 = p(1) + q(1)2  = p + q and 

S2 =p(2) + q(2)2  =2p + 4q 

we know that, S= a = first term and S2 = first term + second term = a + (a + d), 

where d = C.D. 

S2 = 2a + d = 2p + 4q = 2 (p + q) + d = 2p + 2q + d 

= d = 2p + 4q - 2p - 2q = 2q

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