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If <A = (4x + 2)°, the measure of the complementary of <A is equal to (a) (178 + 4x)° (b) (88 – 4x)° (c) (4x + 88)° (d) (6x – 178)°

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If <A = (4x + 2)°, the measure of the complementary of <A is equal to 

(a) (178 + 4x)° (b) (88 – 4x)° (c) (4x + 88)° (d) (6x – 178)°

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(b) Complementary of <A = 90° – <A 

= 90° – (4x + 2)° 

= 90° – 4x° – 2° 

= (88 – 4x)°

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