Question

The van't Hoff's factor of 0.1M Ba (NO₂)₂ solutions are 2.74. The degree of dissociation is- 

(a) 91.3% 

(b) 87% 

(c) 100% 

(d) 74%

Answer 1

Correct Answer is: (b) 87% 

Ba(NO₃)₂ ------> Ba²⁺ + 2NO3^⁻ 

Total number of ions(mole) =1- α + α + 2α

= 1+2α

1+2α =i

α = i-1/2

=2.74-1/2 

=1.74/2

= 0.87

=87%