A = {1, 2, 3,………. 14}
R={(x, y) : 3x – y = 0}
= {(x, y) : y = 3x)
R : {(1,3), (2,6), (3,9), (4,12)}
R is not reflexive as (1,1) ∉ R
R is not symmetric as (1,3) ∈ R but (3,1) ∉ R
R is not transitive as (1,3) ∈ R, (3,9) ∈ R but (1, 9) ∉ R.
To disprove, any counter example is sufficient.