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Sin-1(\(\frac{4}{5}\)) - sec-1(\(\frac{5}{4}\)) = sin-1\(\frac{4}{5}\) + cos-1(\(\frac{4}{5}\))

(A) \(\frac{\pi}{2}\)

(B) 0

(C) π

(D) \(\frac{-\pi}{4}\)

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Best answer

Answer is (A)

sin-1x + cos-1x = \(\frac{\pi}{2}\)

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