Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
27.2k views
in Physics by (60.9k points)
edited by

Two infinitely long straight wires lie in the xy-plane along the lines x = ±R. The wire located at x = +R carries a constant current I1 and the wire located at x = –R carries a constant current I2. A circular loop of radius R is suspended with its centre at (0, 0, 3R) and in a plane parallel to the xy-plane. This loop carries a constant current I in the clockwise direction as seen from above the loop. The current in the wire is taken to be positive if it is in the +j direction. Which of the following statements regarding the magnetic field vector B is (are) true? 

(A) If I1 =I2, then vector B cannot be equal to zero at the origin (0, 0, 0) 

(B) If I1 > 0, and I2 < 0, then vector B can be equal to zero at the origin (0, 0, 0) 

(C) If I1 < 0, and I2 > 0, then vector B can be equal to zero at the origin (0, 0, 0) 

(D) If I= I2, then the z-component of the magnetic field at the centre of the loop is (- μ0I/2R)

Please log in or register to answer this question.

1 Answer

+2 votes
by (150k points)

solution (A, B, D)

(A) If I1 = I2, magnetic field due to infinite wires is equal to zero . So there must be a non–zero magnetic field at O due to the current carrying loop. 

(B) If I1 > 0 & I2 < 0 , magnetic field due to straight lines are along positive z–axis and due to loop it is along negative z–axis. 

(C) If I1 < 0 & I2 > 0 magnetic field due to straight wires are along negative z–axis and due to the loop it is also along negative z–axis

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...