Question

A rod of length L and mass M held vertically Is let go down, without slipping at the point of contact. What is the velocity of the top end at the time of touching ground?

Answer 1

In the experiment, the CM of the rod travels from CM to CM. This change in potential energy appears as rotational kinetic energy. To find Ml about 0,

MI (about CM) = \(\frac {ML^2}{12}\)

using parallel axes theorem

Now, using principle of conservation of energy

To find the velocity of the tip A of rod