Mass of the planet M1 = 3Mearth
Diameter of the planet, R1 = 3Rearth
Let g1 be the acceleration due to gravity on the surface of the earth whose mass Mearth & Radius Rearth Then,
g = \(\frac {GM_{earth}}{R^2_{earth}}\)......(1)
Let g1 be the accleration due to grav-ity. on the surface of the planet whose mass is M1 & Radius is R1 then
g1 = GM1/(R1)2
g1 =
Divide equ (2) by equ (1)
\(\frac {g^1}{g} =\) \(\frac{1}{3}\)
g1 = 9.8/3
= 3.267 m s-2.