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On a semi-circle with AB as diameter, a point C is taken, so that m(∠CAB) = 30°. Find m(∠ACB) and m(∠ABC).

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Given: m(∠CAB)= 30° 

To Find: m(∠ACB) and m(∠ABC). 

Now, ∠ACB = 90° (Angle in semi-circle) 

Now, 

In △ABC, by angle sum property: 

∠CAB + ∠ACB + ∠ABC = 180° 

30° + 90° + ∠ABC = 180° 

∠ABC = 60° 

Answer: ∠ACB = 90° and ∠ABC = 60°

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