Let the heights of the cones be h and 3h and radii of their bases be 3r and r respectively. Then, their volumes are
Volume of first cone (V1) = \(\frac{1}{3}\)π(3r)2h
Volume of second cone (V2) = \(\frac{1}{3}\)πr2(3h)
Now, V1/V2 = \(\frac{3}{1}\)
Ratio of two volumes is 3:1.