Question

Find the value of p for the following distribution whose mean is 16.6.

x:	8	12	15	p	20	25	30
f:	12	16	20	24	16	8	4

Answer 1

\(Mean =\frac{ \sum fx}{N}\)

= \(\frac{(24p\, +\, 1228)}{100}\)

Mean = 16.6 

So, \(\frac{(24p\, +\, 1228)}{100}\) = 16.6 

24p + 1228 = 1660 

24p = 1660 – 1228 = 432 

p = \(\frac{432}{24}\) 

= 18 

The value of p is 18.