Given,
3x – 5y = 20……. (i)
6x – 10y = – 40……. (ii)
For equation (i),
⇒ y = \(\frac{(3x – 20)}{5}\)
When x = 5, we have y = \(\frac{(3(5) – 20)}{5}\) = -1
When x = 0, we have y = \(\frac{(3(0) – 20)}{5}\) = -4
Thus we have the following table giving points on the line 3x – 5y = 20
For equation (ii),
We solve for y:
⇒ y = \(\frac{(6x + 40)}{10}\)
So, when x = 0
y = \(\frac{(6(0) + 40)}{10}\) = 4
And, when x = -5
⇒ y = (6(-5) + 40)/10 = 1
Thus we have the following table giving points on the line 6x – 10y = – 40
Graph of the equations (i) and (ii) is as below:
It is clearly seen that, there is no common point between these two lines.
Hence, the given systems of equations is in-consistent.