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A frequency distribution given the following results : (i) CV = 5, (ii) SD = 2 (iii) Karl Pearson's coefficient of skewness = 0.5. Find the mean and the made of the distribution.

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We know that : C.V = \( \frac{\sigma}{\bar{x}} × 100\)

0.5 = \(\frac{50-z}{2}\)

∴ x̄ = \(\frac{2}{5}\)× 100 = 40

K.P.C.Sk = \(\frac{\bar x-z}{σ}\)

0.5 × 2 = 40 - z

5 = \(\frac{2}{x}\) × 100

∴ z = 40 - 1 = 39.

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