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If x = 2cosθ - cos2θ and y = 2sinθ - sin2θ, prove that dy/dx = tan(3θ/2)

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If x = 2cosθ - cos2θ and y = 2sinθ - sin2θ, prove that dy/dx = tan(3θ/2)

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Given as x = 2cosθ - cos2θ

On differentiating x with respect to θ using chain rule

y = 2sinθ - sin2θ

On differentiating y with respect to θ using chain rule

On dividing eqn (2) by (1)

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