Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
3.1k views
in Physics by (53.2k points)

A conducting sphere of radius 10cm has an unknown charge. If the electric field 20cm from the centre of the sphere is 1.5 x 103N/C and the points radially inward, what is the net change on the sphere?

1 Answer

+1 vote
by (52.4k points)
selected by
 
Best answer

Consider a sphere of radius
R = (=10cm = 0.1 m) and centre O.
Let the charge on the sphere be ‘q’. Further, let ‘P’ be a point at a distance r = 20cm from the centre of the sphere.

The electric field E( = 1.5 x 103NC-1) is directed radially inward as shown. So as to enclose the charged sphere, draw a sphere (gaussian surface) with the point O as centre and r as the radius. As the electric field is radial, it is normal to the gaussian surface everywhere. Therefore, electric flux through the gaussian surface,

ϕ = -E x area of the gaussian surface

∴ ϕ = -E x 4πr2

= -1.5 x 10-2 x 4π(0.2)2

According to Gauss's theorem,

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...