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Analysis shows that nickel oxide has the formula Ni098 O1.00 What fractions of nickel exist as Ni2+ and Ni3+ ions?

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The formula Ni098 O1.00 shows that Ni : O = 0.98 : 1.00 = 98 : 100. 

Thus, if there are 100 O-atoms, then Ni atoms = 98 charge on 100 O2′ ions = 100 x (-2) = - 200 suppose Ni atoms as Ni2+ = x 

Then Ni atoms as Ni3+ = 98 - x 

Total charge on Ni2+ and Ni3+ 

= (+2) x + (+3) (98 - x) = 294 - x 

As metal oxide is neutral, total charge on cations = total charge on anions 

294 - x = 200 

x = 94 

∴ % of Ni as Ni2+ = gx100  98 

= 96% 

% of Ni as Ni3+ = 1000 - 96 = 4.

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