Question

At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

Answer 1

π = CRT 

∴ In the first case, 

4.98 = \(\frac{36}{180}\) × R × 300 = 60R 

In the second case, 1.52 = C × R × 300 

Dividing (ii) by (i), we get C = 0.061 M.