Question

Given the standard electrode potentials, 

K⁺ /K = -2.93V, Ag⁺ /Ag = 0.80V, 

Hg²⁺/Hg = 0.79 V Mg²⁺/Mg = -2,37 V, Cr³⁺/Cr = -0.74 V 

Arrange these metals in their increasing order of reducing power.

Answer 1

The lower the reduction potential, the higher is the reducing power. Hence, the reducing power of the given metals increases in the following order. Ag < Hg < Cr < Mg < K.