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If A = \(\begin{bmatrix} 3 &2 \\[0.3em] 1 & 4\\[0.3em] \end{bmatrix}\), B = \(\begin{bmatrix} 1 &-1 \\[0.3em] -2 & 3\\[0.3em] \end{bmatrix}\) and C = \(\begin{bmatrix} -3 &4 \\[0.3em] 2 & -1\\[0.3em] \end{bmatrix}\). Find 3A – 2B – 4C

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3A - 2B - 4C

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