
B1 = 1.2 × 10-2 T
Inclination of the dipole with Blθ = 15°
Therefore, inclination of the dipole with B2
θ2 = 60 - 15 = 45°
As the dipole is in equilibrium; the torque on the dipole due to the filed B1 is equal and opposite to that due to B2. If M is the magnetic dipole moment of the dipole, then,
MB1 sinθ1= MB2 sinθ2
