The answer is (C) \(\frac{Q}{\sqrt2}\)
Maximum charge on capacitor = q (Given)
The electric energy stored when energy in equally distributed, U'E = \(\frac{1}{2}.\frac{q^2}{C}\)
The energy stored in the capacitor when it is maximally charged, UE = \(\frac{1}{2}.\frac{Q^2}{C}\)
Thus,
Ue = 2U'e
⇒ q = \(\frac{Q}{\sqrt2}\)
Therefore, the energy equally stored between both the field is \(\frac{Q}{\sqrt2}\) .