Let’s assume the length and breadth of the rectangle be x units and y units respectively.
Hence, the area of rectangle = xy sq.units
From the question we have the following cases,
According to the question,
Case 1:
Length is increased by 3 metres
⇒ now, the new length is x+3
Breadth is reduced by 4 metres
⇒ now, the new breadth is y-4
And it’s given, the area of the rectangle is reduced by 67 m2 = xy – 67.
So, the equation becomes
xy – 67 = (x + 3)(y – 4)
xy – 67 = xy + 3y – 4x – 12
4xy – 3y – 67 + 12 = 0
4x – 3y – 55 = 0 —— (i)
Case 2:
Length is reduced by 1 m
⇒ now, the new length is x-1
Breadth is increased by 4 metre
⇒ now, the new breadth is y+4
And it’s given, the area of the rectangle is increased by 89 m2 = xy + 89.
Then, the equation becomes
xy + 89 = (x -1)(y + 4)
4x – y – 93 = 0 —— (ii)
Solving (i) and (ii),
Using cross multiplication, we get
x = 224/8
x = 28
And,
y = 152/8
y = 19
Therefore, the length of rectangle is 28 m and the breadth of rectangle is 19 m.