Question

Obtain the binding energy of the nuclei \(_{26}^{56}Fe\,\,and\,\,_{83}^{209}Bi\) in units of MeV from the following data:
\(m(_{26}^{56}Fe)=55.934939u\)
\(m(_{83}^{209}Bi)= 208.980388u\)

Answer 1

m_p = 1.007825 amu

m_n = 1.008665 amu

The binding energy of the nucleus of the atom \(_Z^AX\) is given by,