Applying KVL to collector circuit, We get,
Vcc = IcRc + Vce
16 = Ic x 4 x 103 + Vce …………. (1)
Put Ic = 0 in equation (1), we get,
VCE ( cut off)
= Vcc
= 16 V
This is cut off point on the x-axis.
Put VCE = 0 in equation (1), we get,
16 = IC x 4 x 103 + 0, IC = 16 x 10-3/4 = 4mA.
This is saturation point on y axis
