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Prove that cotA/(cotA - cot3A) + tanA/(tanA - tan3A) = 1

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Prove that \(\frac{cotA}{cotA - cot3A} + \frac{tanA}{tanA - tan3A}\) = 1

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LHS = \(\frac{cotA}{cotA - cot3A} + \frac{tanA}{tanA - tan3A}\)

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