Question

Solve: x³ + y³ = 3axy

Answer 1

Given x³ + y³ = 3axy 

3x² + 3y²\(\frac{dy}{dx}\) = 3a(x .\(\frac{dy}{dx}\) + y.1)

\(\frac{dy}{dx}\)(3y² – 3ax) = 3ay – 3x² = \(\frac{dy}{dx}\) 

= \(\frac{ay - x^2}{y^2 - ax}\)