Question

Solve: x² . e^{x^2} . log x.

Answer 1

Let y = x² . e^{x^2} . log x. taking log^m both sides 

log y = log(x² . e^{x^2} . logx) logy = log (x² . e^{x^2} . log x) 

differentiate w.r.t x 

log y = log x² + log e^{x^2} + log(logx)