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Differentiate sin2x w.r.t. x2

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Let u = sin2x, v = x2 

Differentiate both w.r.t. x 

\(\frac{du}{dx}\) = 2 sin x. cos x, 

\(\frac{dv}{dx}\) = 2x

∴ \(\frac{du}{dv}\) = \(\frac{\frac{du}{dx}}{\frac{dv}{dx}} = \frac{2sinxcosx}{2x}\)

\(\frac{sinxcosx}{x}\)

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