Question

Evaluate: \(\int\frac{cotx}{3 + log(sinx)}dx\)

Answer 1

\(\int\frac{cotx}{3 + log(sinx)}dx\)

= \(\frac{dt}{t}\)

= log t + c = log(3 + log(sin x)) + c 

put 3 + log(sin x) = t

\(\frac{cosx}{sinx}dx\) = dt

cos x dx = dt