Question

If z₁ = (2 – i), z₂ = (-2 + i), find

(i) Re (z₁z₂/bar z₁)

(ii) Im (1/z₁ bar z₁)

Answer 1

Given as

z₁ = (2 – i) and z₂ = (-2 + i)

(i) Re (z₁z₂/bar z₁)

Now, we shall rationalize the denominator,

Thus, the real value is -2/5

(ii) Im (1/z₁ bar z₁)

Thus, the imaginary value is 0.