
Let the circle inscribed in the equilateral triangle be with a centre O and radius r.
We know that, Area of a Circle = πr2
But, the given that area is 154 cm2.
(22/7) × r2 = 154
r2 = (154 x 7)/22 = 7 × 7 = 49
r = 7 cm
From the figure seen above, we infer that
At point M, BC side is tangent and also at point M, BM is perpendicular to OM.
We know that,
In an equilateral triangle, the perpendicular from vertex divides the side into two halves.
BM = \(\frac{1}{2}\) x BC
Consider the side of the equilateral triangle be x cm.

Therefore, the perimeter of the triangle is found to be 42√3 cm = 42(1.73) = 72.7 cm