Given,
Radius = 5 cm
Length of arc = 3.5 cm
Let θ = angle subtended at the centre of circle
We know that,
Length of arc = θ/360 ∗ 2πr cm
= θ/360 ∗ 2π(5)
From the question, we can equate
3.5 = θ/360 ∗ 2π(5)
3.5 = 10π ∗ θ/360
θ = 360 x 3.5/ (10π)
θ = 126/ π
Now, the area of the sector = θ/360 ∗ πr2
= (126/ π)/ 360 ∗ π(5)2
= 126 x 25 / 360 = 8.75
Hence, the area of the sector = 8.75 cm2